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![Constexpr - Generalized Constant Expressions in C++11 - Cprogramming.com]()
www.cprogramming.comLearn how constexpr and generalized constant expressions make compile time programming easier in C++11 ... There are several improvements in C++11 that promise to allow programs written using C++11 to run faster than ever before. One of those ...瀏覽：1441 -
![c++ - array size and const - Stack Overflow]()
stackoverflow.com2011年1月18日 - Because in C++ array sizes must be constant expressions, not just constant data. Array data, even though const, is not a constant expression. Second ...瀏覽：478
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日期：2024-07-16
2011年10月30日 - The issue here is that const in C doesn't result in a true constant. When you write const int i = 5 what you have is a read-only variable and not a ......
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日期：2024-07-14
2013年9月17日 - It's simply a limitation of the language. The sizes of statically-bounded arrays need to be constant expressions, and unfortunately in C that's only ......
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日期：2024-07-13
2010年10月21日 - It is likely that your Objective-C compiler uses a C compiler as a backend. C (up to C98) only permits constant expressions as array sizes. This is what ......
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日期：2024-07-18
2012年11月14日 - You can use int size = sizeof(codesArr) / sizeof(myStr); as long as you don't pass it as parameter to a function, because then the array will decay into a ......
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日期：2024-07-16
2013年9月20日 - No, the const -ness of j is irrelevant here. C++ currently only supports statically-sized C-arrays. Its size must be a compile-time constant....
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日期：2024-07-18
2012年2月9日 - When creating an array like that, its size must be constant. If you want a ... C++ doesn't allow non-constant values for the size of an array....
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日期：2024-07-15
2005年11月15日 - Need help? Post your question and get tips & solutions from a ... Hi, The following code: #include // const int const_asize = 10; #define ......
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日期：2024-07-15
C++ provides a convenient syntax for declaration of fixed-size arrays: Copy ... The number of elements in the array is given by the constant-expression. The first ......
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