search:not found for architecture i386相關網頁資料

      • rritw.com
        ... not found for architecture i386 clang: error: linker command failed with exit code 1 (use -v to see invocation) 搞了一陣之後,才發現原來xcode是有一個很嚴格的引用規定的,也是C++的編譯規則,每一個編譯的文件都必須在命令行裏面,而我只是因为有一個 沒有 ...
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      • www.myexception.cn
        我的異常網之'symbol(s) not found for architecture i386'專題提供權威的'symbol(s) not found for architecture i386'解決方案,歡迎您的到來。 ... symbol(s) not found for architexture i386 報錯 我靠啊,今天下午出現了個這個錯誤,找了好多資料,發現讓添加lib和 ...
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    日期:2024-07-07
    in ShareKitTestAppDelegate.o ld: symbol(s) not found for architecture i386 collect2: ld returned 1 exit status Often, as far as I know, these problems arise if header files are wrongly imported. But I don't see any error here in the following code ......
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    日期:2024-07-09
    ld: symbol(s) not found for architecture i386,xj179的網易博客,網易博客, ... 溫馨提示!由於新浪微博認證機制調整,您的新浪微博帳號綁定已過期,請重新綁定!立即重新綁定新浪微博》 | 關閉...
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    日期:2024-07-08
    Someone can explain me what is it telling by "symbol(s) not found for architecture i386". xcode xcode4 share | improve this question edited Jan 15 '13 at 19:06 Codo 27.5k 4 41 82 asked Jan 15 '13 at 18:34 Dimitri 379 1 8 22 add comment 1 Answer active old...
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    日期:2024-07-13
    我的異常網之'ld: symbol(s) not found for architecture i386'專題提供權威的'ld: symbol(s) not found for architecture i386'解決方案,歡迎您的到來。...
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    日期:2024-07-08
    “ld: symbol(s) not found for architecture i386”錯誤的一般解決辦法_jianyunli042_新浪博客,jianyunli042, ... 1、檢查工程設置Search Paths裡的Framework Search Paths、Header Search Paths、Library Search Paths的路徑設置,看設置路徑是否正確,另外還要註意 ......
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    日期:2024-07-08
    ... not found for architecture i386 clang: error: linker command failed with exit code 1 (use -v to see invocation) 搞了一陣之後,才發現原來xcode是有一個很嚴格的引用規定的,也是C++的編譯規則,每一個編譯的文件都必須在命令行裡面,而我只是因為有一個 沒有 ......
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    日期:2024-07-07
    今天搞網路連接,網上說將Reachability以及庫SystemConfiguration導入到項目中就可以用了。但是我導入就遇到symbol(s) not found for architecture i386這樣一個錯誤。網路上都說是文件導入出問題了。說不能直接將庫文件拖進項目中。首先這種說法有問題,可以重 ......
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    日期:2024-07-14
    ... not found for architecture i386 clang: error: linker command failed with exit code 1 (use -v to see invocation) 搞了一陣之後,才發現原來xcode是有一個很嚴格的引用規定的,也是C++的編譯規則,每一個編譯的文件都必須在命令行裡面,而我只是因為有一個 沒有 ......