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轉置矩陣的證明問題?......20點 - Yahoo!奇摩知識+
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日期:2024-08-04
A = [aij], 則A^t = [aji] 1. (A + B)^t = ( [aij] + [bij] )^t = ( [aij + bij] ) ^t = [aji + bji] = [aji] +
[bji] = A^t + B^t 2. (cA)^t ......看更多